1 Number System • Recurring Decimals निम्नलिखित व्यंजक का मान ज्ञात कीजिए: (0.333333...) × 99 + (0.666666...) × 102 Evaluate the expression: (0.333333...) × 99 + (0.666666...) × 102. सेव करें Save सेव्ड Saved A. 99 99 B. 100 100 C. 101 101 D. 102 102 उत्तर और व्याख्या देखें Show answer and explanation सही उत्तर: C Correct Answer: C 0.333333... = 1/3 और 0.666666... = 2/3। अतः (1/3 × 99) + (2/3 × 102) = 33 + 68 = 101। 0.333333... = 1/3 and 0.666666... = 2/3. Therefore, (1/3 × 99) + (2/3 × 102) = 33 + 68 = 101.
2 Number System • Recurring Decimals x = 0.37373737... को p/q के रूप में लिखिए। Write x = 0.37373737... in the form p/q. सेव करें Save सेव्ड Saved A. x = 37/100 x = 37/100 B. x = 37/99 x = 37/99 C. x = 37/101 x = 37/101 D. x = 37/102 x = 37/102 उत्तर और व्याख्या देखें Show answer and explanation सही उत्तर: B Correct Answer: B मान लें x = 0.373737...। तब 100x = 37.373737...। घटाने पर 100x - x = 37, अर्थात 99x = 37। इसलिए x = 37/99। Let x = 0.373737.... Then 100x = 37.373737.... Subtracting gives 100x - x = 37, so 99x = 37. Therefore, x = 37/99.