Statics MCQs

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Statics MCQs

श्रेणी: Mathematics | विषय: Advanced Mathematics | टॉपिक: Statics

1
Advanced Mathematics • Statics
The Cartesian equation of common catenary is: The Cartesian equation of common catenary is:
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सही उत्तर: B Correct Answer: B
The curve formed by a uniform flexible chain hanging under its own weight is the catenary y = c cosh(x/c).
The curve formed by a uniform flexible chain hanging under its own weight is the catenary y = c cosh(x/c).
2
Advanced Mathematics • Statics
If P and Q are two non-intersecting forces whose directions are perpendicular, then the ratio of the distances of the central axis from their lines of action is represented as: If P and Q are two non-intersecting forces whose directions are perpendicular, then the ratio of the distances of the central axis from their lines of action is represented as:
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सही उत्तर: C Correct Answer: C
For two perpendicular non-intersecting forces, the distances of the central axis from their respective lines of action are in the inverse-square ratio of the forces, giving Q^2 : P^2 in the stated order.
For two perpendicular non-intersecting forces, the distances of the central axis from their respective lines of action are in the inverse-square ratio of the forces, giving Q^2 : P^2 in the stated order.
3
Advanced Mathematics • Statics
Two equal uniform rods AB and AC, each of length 2b, are freely joined at A and rest on a smooth vertical circle of radius a. If 2theta is the angle between them, then: Two equal uniform rods AB and AC, each of length 2b, are freely joined at A and rest on a smooth vertical circle of radius a. If 2theta is the angle between them, then:
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सही उत्तर: D Correct Answer: D
Applying the equilibrium condition to the symmetric rod configuration gives b sin^3(theta)=a cos(theta), as marked in the source paper.
Applying the equilibrium condition to the symmetric rod configuration gives b sin^3(theta)=a cos(theta), as marked in the source paper.
4
Advanced Mathematics • Statics
A solid frustum of a paraboloid of revolution of height h and latus rectum 4a rests with its vertex on the vertex of a paraboloid of revolution whose latus rectum is 4b. The equilibrium is stable if: A solid frustum of a paraboloid of revolution of height h and latus rectum 4a rests with its vertex on the vertex of a paraboloid of revolution whose latus rectum is 4b. The equilibrium is stable if:
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सही उत्तर: A Correct Answer: A
The stability condition obtained by comparing the centre-of-gravity displacement with the supporting-paraboloid geometry is h<3ab/(a+b).
The stability condition obtained by comparing the centre-of-gravity displacement with the supporting-paraboloid geometry is h<3ab/(a+b).

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