Complex Analysis MCQs

महत्वपूर्ण बहुविकल्पीय प्रश्नों का अभ्यास करें। उत्तर, व्याख्या, विषय और परीक्षा टैग के साथ।

Complex Analysis MCQs

श्रेणी: Mathematics | विषय: Advanced Mathematics | टॉपिक: Complex Analysis

1
Advanced Mathematics • Complex Analysis
Which of the following statements is INCORRECT? Which of the following statements is INCORRECT?
सेव करें Save सेव्ड Saved
सही उत्तर: B Correct Answer: B
Continuity of the first partial derivatives of u and v alone does not ensure complex differentiability; the Cauchy-Riemann equations must also hold at the point. Option B is the answer marked in the source paper.
Continuity of the first partial derivatives of u and v alone does not ensure complex differentiability; the Cauchy-Riemann equations must also hold at the point. Option B is the answer marked in the source paper.
2
Advanced Mathematics • Complex Analysis
Using the Residue Theorem, evaluate the integral of (5z - 2)/(z(z - 1)) dz over the contour C: |z| = 2. Using the Residue Theorem, evaluate the integral of (5z - 2)/(z(z - 1)) dz over the contour C: |z| = 2.
सेव करें Save सेव्ड Saved
सही उत्तर: B Correct Answer: B
The contour contains the poles z = 0 and z = 1. Their residues are 2 and 3, whose sum is 5. Thus the integral is 2pi i x 5 = 10pi i.
The contour contains the poles z = 0 and z = 1. Their residues are 2 and 3, whose sum is 5. Thus the integral is 2pi i x 5 = 10pi i.
3
Advanced Mathematics • Complex Analysis
If a function f(z), defined on some domain D of the complex plane, is differentiable on D, it is said to be: If a function f(z), defined on some domain D of the complex plane, is differentiable on D, it is said to be:
सेव करें Save सेव्ड Saved
सही उत्तर: A Correct Answer: A
A complex function differentiable at every point of a domain is analytic, or holomorphic, on that domain.
A complex function differentiable at every point of a domain is analytic, or holomorphic, on that domain.
4
Advanced Mathematics • Complex Analysis
Let f(r cos(theta) + i r sin(theta)) = u(r,theta) + iv(r,theta). For f to be differentiable at (r,theta), the Cauchy-Riemann equations state that: Let f(r cos(theta) + i r sin(theta)) = u(r,theta) + iv(r,theta). For f to be differentiable at (r,theta), the Cauchy-Riemann equations state that:
सेव करें Save सेव्ड Saved
सही उत्तर: B Correct Answer: B
In polar coordinates the Cauchy-Riemann equations are u_r = v_theta/r and v_r = -u_theta/r.
In polar coordinates the Cauchy-Riemann equations are u_r = v_theta/r and v_r = -u_theta/r.
5
Advanced Mathematics • Complex Analysis
If C is a positively oriented simple closed contour within and on which f is analytic, except for a finite number of singular points z_k (k = 1,2,...,n) interior to C, then the Residue Theorem states that: If C is a positively oriented simple closed contour within and on which f is analytic, except for a finite number of singular points z_k (k = 1,2,...,n) interior to C, then the Residue Theorem states that:
सेव करें Save सेव्ड Saved
सही उत्तर: B Correct Answer: B
By the Residue Theorem, the contour integral equals 2pi i times the sum of the residues at all singularities inside C.
By the Residue Theorem, the contour integral equals 2pi i times the sum of the residues at all singularities inside C.
6
Advanced Mathematics • Complex Analysis
Let C denote the boundary of the circle with radius 3 around the centre z_1 = 2 + i. Calculate the integral I = integral_C e^(az)/(z - 2 - i) dz. Let C denote the boundary of the circle with radius 3 around the centre z_1 = 2 + i. Calculate the integral I = integral_C e^(az)/(z - 2 - i) dz.
सेव करें Save सेव्ड Saved
सही उत्तर: C Correct Answer: C
By Cauchy's integral formula, the integral equals 2pi i times e^(az) evaluated at z = 2 + i, giving 2pi i e^(a(2 + i)).
By Cauchy's integral formula, the integral equals 2pi i times e^(az) evaluated at z = 2 + i, giving 2pi i e^(a(2 + i)).
7
Advanced Mathematics • Complex Analysis
Compute the integral of cos(z/2) dz from 0 to pi + 2i. Compute the integral of cos(z/2) dz from 0 to pi + 2i.
सेव करें Save सेव्ड Saved
सही उत्तर: A Correct Answer: A
An antiderivative is 2sin(z/2). At z = pi + 2i this is 2sin(pi/2 + i) = 2cosh(1) = e + 1/e; the lower endpoint contributes zero.
An antiderivative is 2sin(z/2). At z = pi + 2i this is 2sin(pi/2 + i) = 2cosh(1) = e + 1/e; the lower endpoint contributes zero.
8
Advanced Mathematics • Complex Analysis
Select the function f(z) from below that is analytic on the unit disk |z|<1. Select the function f(z) from below that is analytic on the unit disk |z|<1.
सेव करें Save सेव्ड Saved
सही उत्तर: B Correct Answer: B
Option B is cos(x+iy)=cos(z), which is entire and therefore analytic on the unit disk.
Option B is cos(x+iy)=cos(z), which is entire and therefore analytic on the unit disk.
9
Advanced Mathematics • Complex Analysis
The power-series expansion sum of z^(4n+1)/(2n)! for n=0,1,2,... represents which analytic function? The power-series expansion sum of z^(4n+1)/(2n)! for n=0,1,2,... represents which analytic function?
सेव करें Save सेव्ड Saved
सही उत्तर: D Correct Answer: D
Since cosh(z^2)=sum z^(4n)/(2n)!, multiplying by z gives sum z^(4n+1)/(2n)!.
Since cosh(z^2)=sum z^(4n)/(2n)!, multiplying by z gives sum z^(4n+1)/(2n)!.
10
Advanced Mathematics • Complex Analysis
The Taylor-series expansion sum of (-1)^n z^(2n+1)/(2n+1)! for n=0,1,2,... represents which analytic function? The Taylor-series expansion sum of (-1)^n z^(2n+1)/(2n+1)! for n=0,1,2,... represents which analytic function?
सेव करें Save सेव्ड Saved
सही उत्तर: B Correct Answer: B
This is the standard Maclaurin expansion z-z^3/3!+z^5/5!-..., which equals sin(z).
This is the standard Maclaurin expansion z-z^3/3!+z^5/5!-..., which equals sin(z).

श्रेणी अनुसार अभ्यास करें

वर्तमान परीक्षा टैग के भीतर किसी श्रेणी को चुनकर अभ्यास करें।

विषय अनुसार अभ्यास करें

किसी विषय को चुनकर उसी विषय के सभी MCQs का अभ्यास करें।

टॉपिक अनुसार अभ्यास करें

किसी एक टॉपिक पर केंद्रित अभ्यास के लिए कार्ड चुनें।

परीक्षा अनुसार अभ्यास करें

अन्य परीक्षा टैग के अनुसार प्रश्नों का अभ्यास करें।