2
Mathematics
• Conic Sections
Find the focus of the conic x^2 + 19 - 8x - y = 0.
Find the focus of the conic x^2 + 19 - 8x - y = 0.
सही उत्तर: A
Correct Answer: A
Rewriting gives (x - 4)^2 = y - 3. Comparing with (x-h)^2 = 4a(y-k), we get a = 1/4, so the focus is (4, 3 + 1/4) = (4, 3.25).
Rewriting gives (x - 4)^2 = y - 3. Comparing with (x-h)^2 = 4a(y-k), we get a = 1/4, so the focus is (4, 3 + 1/4) = (4, 3.25).