Mathematics MCQs for JSSC PGT Mathematics Exam

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Mathematics MCQs for JSSC PGT Mathematics Exam

श्रेणी: Mathematics | परीक्षा: JSSC PGT Mathematics Exam

11
Geometry • Coordinate Geometry
Find the rectangular coordinates of the point with cylindrical coordinates (2, 2pi/3, 1). Find the rectangular coordinates of the point with cylindrical coordinates (2, 2pi/3, 1).
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सही उत्तर: A Correct Answer: A
Using x = r cos(theta), y = r sin(theta), z = z, we get x = 2 cos(2pi/3) = -1, y = 2 sin(2pi/3) = sqrt(3), and z = 1.
Using x = r cos(theta), y = r sin(theta), z = z, we get x = 2 cos(2pi/3) = -1, y = 2 sin(2pi/3) = sqrt(3), and z = 1.
12
Advanced Mathematics • Graph Theory
In a graph, the number of vertices with odd degrees is always: In a graph, the number of vertices with odd degrees is always:
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सही उत्तर: C Correct Answer: C
By the handshaking lemma, the sum of all vertex degrees is even. Therefore, vertices of odd degree must occur in an even number.
By the handshaking lemma, the sum of all vertex degrees is even. Therefore, vertices of odd degree must occur in an even number.
13
Advanced Mathematics • Graph Theory
If every point of G has even degree, then G is a: If every point of G has even degree, then G is a:
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सही उत्तर: C Correct Answer: C
A connected graph has an Euler circuit if and only if every vertex has even degree; hence it is Eulerian.
A connected graph has an Euler circuit if and only if every vertex has even degree; hence it is Eulerian.
14
Advanced Mathematics • Dynamics
A solid homogeneous cone of height h and semi-vertical angle alpha oscillates about a diameter of its base. The length of the simple equivalent pendulum is: A solid homogeneous cone of height h and semi-vertical angle alpha oscillates about a diameter of its base. The length of the simple equivalent pendulum is:
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सही उत्तर: B Correct Answer: B
For a physical pendulum, the equivalent length is I/(Md), where I is the moment of inertia about the axis and d is the distance of the centre of mass from it. For the stated cone this reduces to (h/5)(2 + 3tan^2(alpha)).
For a physical pendulum, the equivalent length is I/(Md), where I is the moment of inertia about the axis and d is the distance of the centre of mass from it. For the stated cone this reduces to (h/5)(2 + 3tan^2(alpha)).
15
Advanced Mathematics • Complex Analysis
Which of the following statements is INCORRECT? Which of the following statements is INCORRECT?
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सही उत्तर: B Correct Answer: B
Continuity of the first partial derivatives of u and v alone does not ensure complex differentiability; the Cauchy-Riemann equations must also hold at the point. Option B is the answer marked in the source paper.
Continuity of the first partial derivatives of u and v alone does not ensure complex differentiability; the Cauchy-Riemann equations must also hold at the point. Option B is the answer marked in the source paper.
16
Advanced Mathematics • Vector Calculus
Find the directional derivative D_u f(x,y) at (x,y) = (1,2), where f(x,y) = x^3 - 3xy + 4y^2 and u is the unit vector in the direction theta = pi/6. Find the directional derivative D_u f(x,y) at (x,y) = (1,2), where f(x,y) = x^3 - 3xy + 4y^2 and u is the unit vector in the direction theta = pi/6.
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सही उत्तर: A Correct Answer: A
At (1,2), grad f = (3x^2 - 3y, -3x + 8y) = (-3,13). Dotting it with (cos(pi/6), sin(pi/6)) gives (13 - 3sqrt(3))/2.
At (1,2), grad f = (3x^2 - 3y, -3x + 8y) = (-3,13). Dotting it with (cos(pi/6), sin(pi/6)) gives (13 - 3sqrt(3))/2.
17
Advanced Mathematics • Differential Equations
The integrating factor for the differential equation y(xy + 2x^2y^2) dx + x(xy - x^2y^2) dy = 0 is: The integrating factor for the differential equation y(xy + 2x^2y^2) dx + x(xy - x^2y^2) dy = 0 is:
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सही उत्तर: C Correct Answer: C
Multiplying by 1/(3x^3y^3) makes the differential form exact; this is the integrating factor marked in the source paper.
Multiplying by 1/(3x^3y^3) makes the differential form exact; this is the integrating factor marked in the source paper.
18
Advanced Mathematics • Graph Theory
Circumference of a cyclic graph is defined as: Circumference of a cyclic graph is defined as:
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सही उत्तर: B Correct Answer: B
The circumference of a graph is the length, measured by number of edges, of its longest cycle.
The circumference of a graph is the length, measured by number of edges, of its longest cycle.
19
Advanced Mathematics • Mathematical Modelling
If x(t) denotes the number of susceptibles and y(t) denotes the number of infectives at time t, in a homogeneous group of (n + 1) individuals, the simple epidemic model without removal is given by the equation (where beta > 0 is the contact rate): If x(t) denotes the number of susceptibles and y(t) denotes the number of infectives at time t, in a homogeneous group of (n + 1) individuals, the simple epidemic model without removal is given by the equation (where beta > 0 is the contact rate):
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सही उत्तर: B Correct Answer: B
With no removal, x + y = n + 1 and susceptibles decrease at rate dx/dt = -beta xy. Substituting y = n + 1 - x gives dx/dt = -beta x(n + 1 - x).
With no removal, x + y = n + 1 and susceptibles decrease at rate dx/dt = -beta xy. Substituting y = n + 1 - x gives dx/dt = -beta x(n + 1 - x).
20
Advanced Mathematics • Partial Differential Equations
The steady-state solution mu(x,t) = mu_s(x) of the heat equation mu_t = a^2 mu_xx satisfying the conditions mu(0,t) = -1 and mu(2,t) = 1 is: The steady-state solution mu(x,t) = mu_s(x) of the heat equation mu_t = a^2 mu_xx satisfying the conditions mu(0,t) = -1 and mu(2,t) = 1 is:
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सही उत्तर: B Correct Answer: B
At steady state, mu_xx = 0, so mu_s(x) = Ax + B. The boundary values give B = -1 and A = 1; hence mu_s(x) = -1 + x.
At steady state, mu_xx = 0, so mu_s(x) = Ax + B. The boundary values give B = -1 and A = 1; hence mu_s(x) = -1 + x.

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